用Collections.sort方法对list排序有两种方法
第一种是list中的对象实现Comparable接口
如下
/** * 根据order对User排序 */ public class User implements Comparable{ private String name; private Integer order; public String getName() { return name; } public void setName(String name) { this.name = name; } public Integer getOrder() { return order; } public void setOrder(Integer order) { this.order = order; } public int compareTo(User arg0) { return this.getOrder().compareTo(arg0.getOrder()); } } 测试一下: public class Test{ public static void main(String[] args) { User user1 = new User(); user1.setName("a"); user1.setOrder(1); User user2 = new User(); user2.setName("b"); user2.setOrder(2); List list = new ArrayList (); //此处add user2再add user1 list.add(user2); list.add(user1); Collections.sort(list); for(User u : list){ System.out.println(u.getName()); } } }
输出结果如下
a
b
第二种方法是根据Collections.sort重载方法来实现
例如:
/**
* 根据order对User排序
*/
public class User { //此处无需实现Comparable接口
private String name;
private Integer order;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Integer getOrder() {
return order;
}
public void setOrder(Integer order) {
this.order = order;
}
}
主类中这样写即可(HastSet——>List——>sort进行排序):
public class Test {
public static void main(String[] args) {
User user1 = new User();
user1.setName("a");
user1.setPrice(11);
User user2 = new User();
user2.setName("b");
user2.setPrice(2);
Set Hset = new HashSet();
Hset.add(user2);
Hset.add(user1);
List list = new ArrayList();
list.addAll(Hset);
Collections.sort(list,new Comparator(){
public int compare(User arg0, User arg1) {
return arg0.getPrice().compareTo(arg1.getPrice());
}
});
for(User u : list){
System.out.println(u.getName());
}
} 输出结果如下:
a
b
默认为升序,将
return arg0.getOrder().compareTo(arg1.getOrder());
改为:
return arg1.getOrder().compareTo(arg0.getOrder());
就成降序的了。